Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
The | 14648 | 934 | 18 | 51.8889 |
On | 780 | 45 | 1 | 45.0000 |
He | 3061 | 155 | 4 | 38.7500 |
It | 2760 | 89 | 3 | 29.6667 |
But | 2037 | 69 | 3 | 23.0000 |
We | 2488 | 132 | 6 | 22.0000 |
And | 1387 | 62 | 3 | 20.6667 |
While | 594 | 20 | 1 | 20.0000 |
To | 449 | 37 | 2 | 18.5000 |
She | 1199 | 55 | 3 | 18.3333 |
We’re | 211 | 18 | 1 | 18.0000 |
That’s | 299 | 18 | 1 | 18.0000 |
In | 2655 | 104 | 6 | 17.3333 |
As | 1076 | 34 | 2 | 17.0000 |
It’s | 1098 | 64 | 4 | 16.0000 |
That | 779 | 32 | 2 | 16.0000 |
There’s | 198 | 15 | 1 | 15.0000 |
After | 611 | 29 | 2 | 14.5000 |
They | 1394 | 85 | 6 | 14.1667 |
What | 631 | 38 | 3 | 12.6667 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
be able | 256 | 1 | 17 | 0.0588 |
p.m | 103 | 1 | 13 | 0.0769 |
parts | 182 | 1 | 12 | 0.0833 |
kind | 399 | 2 | 22 | 0.0909 |
place in | 126 | 1 | 11 | 0.0909 |
sort of | 105 | 1 | 10 | 0.1000 |
a number | 211 | 1 | 10 | 0.1000 |
aware | 148 | 2 | 19 | 0.1053 |
responsible | 154 | 1 | 9 | 0.1111 |
Sea | 50 | 1 | 9 | 0.1111 |
fellow | 118 | 1 | 9 | 0.1111 |
lots | 104 | 1 | 8 | 0.1250 |
guard | 84 | 1 | 8 | 0.1250 |
honor | 91 | 1 | 8 | 0.1250 |
expected | 498 | 2 | 16 | 0.1250 |
respond | 93 | 1 | 8 | 0.1250 |
access | 407 | 3 | 22 | 0.1364 |
dealing | 75 | 1 | 7 | 0.1429 |
shift | 78 | 1 | 7 | 0.1429 |
types | 75 | 1 | 7 | 0.1429 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II